The Science and Technology of Space

CONTENTS OF CURRICULUM UNIT 07.07.02

  1. Unit Guide
  1. Introduction
  2. Objectives
  3. Rationale
  4. Content
  5. Strategies
  6. Classroom Activities
  7. Teacher Resources
  8. Student Resources
  9. Appendix I
  10. Appendix II
  11. References

Beyond The Atom: Interpreting the Origin of the Elements

Ram Bhagat

Published September 2007

Tools for this Unit:

Appendix II

Interaction Energy

E ~ kT (k = 1.38 x 10 - 2 3 JK - 1)

Electrovolts (eV), where 1 eV = 1.60 x 10 - 1 9J

MeV = 10 6 eV

GeV = 10 9 eV

Calculate the interaction energy when the temperature is 10 1 4 K. Express your answer in Joules and GeV.

Solution:

E ~ kT = (1.38 x 10 - 2 3 JK - 1) (10 1 4 K) = 1.38 x 10 - 9J

in terms of GeV

(1.38 x 10 - 9J) / (1.60 x 10 - 1 9JeV - 1) = 8.63 x 10 9eV = 8.63 GeV

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